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(F)=3F^2-5F+6
We move all terms to the left:
(F)-(3F^2-5F+6)=0
We get rid of parentheses
-3F^2+F+5F-6=0
We add all the numbers together, and all the variables
-3F^2+6F-6=0
a = -3; b = 6; c = -6;
Δ = b2-4ac
Δ = 62-4·(-3)·(-6)
Δ = -36
Delta is less than zero, so there is no solution for the equation
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